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3^2x-1-4/3^x=5/3
We move all terms to the left:
3^2x-1-4/3^x-(5/3)=0
Domain of the equation: 3^x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3^2x-4/3^x-1-(+5/3)=0
We get rid of parentheses
3^2x-4/3^x-1-5/3=0
We calculate fractions
3^2x-1=0
We move all terms containing x to the left, all other terms to the right
3^2x=1
x=1/1
x=1
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